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Orbits
We can write expressions for both the angular momentum and the total energy. If
pθ is the magnitude of the momentum in the tangential direction, then
since this perpendicular to , L = rpθ. But pθ = mvθ = m
= mr
= mr
.
Hence L = r(mr
) = mr2
. Hence:
L = mr2![]() |
E = 1/2m![]() ![]() ![]() |
![]() ![]() ![]() ![]() ![]() ![]() ![]() |
![]() ![]() |
ε = ![]() |
We can also find the maximum and minimum values of r. The minimum occurs
where the expression for 1/r is a maximum. This is when cosθ = 1 and
the maximum is therefore . Thus:
rmin = ![]() |
rmax = ![]() |
We can also take the equation and using r2 = x2 + y2, and cosθ = x/r, we can write:
x2 + y2 = ![]() ![]() ![]() |
The orbits are determined by the various values that ε can take.
When ε = 0, the expression for ε tells us that E = - . The negative value of the energy just means that the
potential energy is more negative than the kinetic energy is positive. In this
case we have rmin = rmax =
. The particle is trapped
at the very bottom of a potential well, and the radius does not change as it
goes around the orbit, hence forming a circle. Substituting this value for r
into the energy we have E = -
. Note that we could have derived
this directly by summing the potential energy we found for a circular orbit with
the kinetic energy (Gravitational Potential Energy).
E = 1/2mv2 + U = ![]() ![]() ![]() |
Elliptical orbits occur when 0 < ε < 1. This means that - < E < 0. Again the particle is trapped in a potential
well, oscillating now between rmin and rmax.
![]() ![]() |
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