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Predict the absolute stereochemical configuration for the product of this single
SN2 attack:
It's not necessary to determine the absolute configuration of the molecule before
SN2 attack,
but I've included it for clarity's sake.
The small numbers one through four refer to the CIP** priorities of the
branches.
After SN2 substitution, the molecule has the following conformation:
Attack has occurred with inversion of configuration, and the absolute configuration has changed from "R"
to "S."
Problem :
Draw the transition state of the following SN2 reaction (from problem #1):
Problem :
Given the steric and molecular orbital
explanations for
backside attack, explain why the following SN2 reaction does not occur.
The nucleophile, tert-butoxide, must get to the σ C-Br
antibond for an SN2 reaction to occur. The path to the
antibond is blocked by the bulky tert-butyl groups attached to the
stereocenter. The nucleophile also has a bulky ter-butyl tail. It
cannot reach the antibond due to steric clash with the tert-butyl
groups. This effect is explained in the $\mbox{S}_{\mbox{N}}2 \mbox{ vs.
E}_2$ section of this SparkNote.
Problem :
Will molecule A or B undergo a faster SN2 reaction?
A will undergo a faster SN2 reaction. A has a more stable
SN2 transition state
because the partial negative charge on the α-carbon will be
hyperconjugated** into the ring's Π electron
system.
More stable transition states translate into faster reactions. Thus A is faster than B.